Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving `1.0g` of polymer of molar mass `185,000` in `450mL` of water at `37^(@)C`.

Explanation

Given `V=450" mL "=0.45L`
`T=37^(@)C=310K`
`R=8.314kPa" L "K^-1" "mol^(-1)`
To find:
`pu=?`
solution: Applying the formula,
`pi=CRT=(n)/(V)RT`
`n=(1.0g)/(185,000g" "mol^(-1))`
`thereforeP=(1)/(185,000)xx(1)/(0.45)xx8.314`
`xx10^(3)Pa" "LK^(-1)" "mol^(-1)" "xx310K`
`=30.96Pa`