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At 300K,36g of glucose present per litre...

At `300K,36g` of glucose present per litre in its solution had an osmotic pressure `4.98 ` bar. If the osmotic pressure of solution is `1.52` bar at the same temperature, what would be its concentration.

Text Solution

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`pi=CRT`
`4.98=(W_(1))/(M_(1))xxRxx300`
`4.98=(36)/(180)xxRxx300`
4.98=60 R
In second case `1.52=CxxRxx300`
Diving equation (ii) by equation (i), we get
`C=(60xx1.52)/(300xx4.98)=0.06M`
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