If the solubility product of `CuS` is `6xx10^(-16)`, calculate the maximum molarity of `CuS` in aqueous solution.

Explanation

`CuS harr Cu^(2+)+S^(2-), K_(sp)=6xx10^(-16)`
Maximum molarity of CuS in aqueous solution means solubility of CuS.
Let the solubility of CuS be S mol `L^(-1)`
`therefore K_(sp)=[Cu^(2+)][S]^(2-)`
`6xx10^(-16)=SxxS=S^(2)`
` therefore S=sqrt(6xx10^(-16))=2.45xx10^(-8) " mol" L^(-1)`.