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Henry's law constant for the molality of...

Henry's law constant for the molality of methane in benzene at `298K `is `4.27xx10^(5)mm Hg`. Calculate the solubility of methane in benzene at `298 K` under `760 mm Hg`.

Text Solution

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Using relatio `P=H_(H)x`
`thereforex=(P)/(K_(H))=(760" mm Hg")/(4*27xx10^(5)" mm Hg")=1*78xx10^(-3)`
i.e., mole fraction of methane in benzene
`=1*78xx10^(-3)`.
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