If for distribution of 18 observations `sum(x_i-5)=3a n dsum(x_i-5)^2=43 ,` find the mean and standard deviation.

Explanation

Given,

`sum(x_i-5)=3 `

and `sum(x_i-5)^2=43`

So,`Mean=A+(sum(x_i-5))/(18)`

`=5+3/(18)`

`=5.17`


Variance=`sqrt(sum(x_i-5)^2/n-(sum(x_i-5)/n)^2)`

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