A battery of 10V is connected to a resis...

A battery of 10V is connected to a resistance of `20Omega` through a variable resistance R. If the variable resistance R is increased at the rate of `5Omega" min"^(-1)`, then the amount of charge that passes through the battery in 4 min is

`120 C`

`120 log_(e)(2)C`

`(120)/(log_(e)(2))C`

`(60)/(log_(e)(2))C`

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