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Calculate DeltaH when 2 moles of solid b...

Calculate `DeltaH` when 2 moles of solid benzoic acid undergo complete combustion at 300 K if
`C_(6)H_(5)COOH(s)+(15)/(2)O_(2)(g)to7CO_(2)(g)+3H_(2)O(l)`
`DeltaU_(reaction)=-750 kJ//`mole

A

`-1.247kJ`

B

`-2.494kJ`

C

`+2.494kJ`

D

`+1.247kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
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Caalculate DeltaH when 2 moles of solid benzoic acid undergo complete combustion at 300 K if C_(6)H_(5)COOH(s)+(15)/(2)O_(2)(g)to7CO_(2)(g)+3H_(2)O(l) DeltaU_(reaction)=-750kJ//"mole"

The value of DeltaH-DeltaU when 2 moles of solid benzoic acid undergoes combustion at 300 K is given by :

Consider the reaction at 300K C_(6)H_(6)(l)+(15)/(2)O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l),DeltaH=-3271 kJ What is DeltaU for the combustion of 1.5 mole of benzene at 27^(@)C ?

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Calculate standard free energy change from the free energy of formation data for the following reaction, C_(6)H_(6)(l)+(15)/(2)O_(2)(s)to 6CO_(2)(g)+3H_(2)O(g) . Delta_(f)G^(theta)[C_(6)H_(6)(l)]=172.8 kJ/mol Delta_(f)G^(theta)[CO_(2)(g)]=-394.4 kJ/mol Given that. Delta_(f)G^(theta)[CO_(2)(g)]=394.4 kJ/mol Delta_(r )G^(theta)[H_(2)O(l)]=-228.6 kJ/mol

At 27^(@)C for reaction, C_(6)H_(6)(l)+(15)/(2)O_(2)(g)to6CO_(2)(g)+3H_(2)O(l) proceeds spontaneously because the magnitude of

Calculate the standard Gibbs enegry change for the combustion of alpha-D glucose at 300K . C_(6)H_(12)O_(6)(s) +6O_(2)(g) rarr 6CO_(2)(g) +6H_(2)O(l) Given the standard enthalpies of formation (kJ mol^(-1)) C_(6)H_(12)O_(6) =- 1274.5, CO_(2) =- 393.5, H_(2)O =- 285.8 . Entropies (J K mol^(-1)) C_(6)H_(12)O_(6) = 212.1, O_(1) = 205.0, CO_(2) =213, H_(2)O = 69.9

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