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How many carbon atoms are present in 0.3...

How many carbon atoms are present in `0.35` mole of `C_(6)H_(12)O_(6)` ?
`("Given : N"_(A)=6.023xx10^(23))`

A

`1.26xx10^(2)" carbon atoms"`

B

`1.26xx10^(24)" carbon atoms"`

C

`1.26xx10^(44)" carbon atoms"`

D

`1.26xx10^(48)" carbon atoms"`

Text Solution

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The correct Answer is:
B
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