If two variates `Xa n dY` are connected by the relation `Y=(a X+b)/c ,w h e r ea ,b ,c` are constants such that `a c<0,t h e n` (a) `sigma_gamma=a/csigma_X` (b) `sigma_gamma=-a/csigma_X` (c) `sigma_gamma=a/csigma_X+b` (d) none of these

Explanation

Given, `y= (aX+b​)/c`

So,
`σ_Y​=σ(aX+b​)/c=(a/c)σ_x`

and `a/c<0`
therefore `a` and `c` are of opposite sign.

therefore, ​

`σ_Y​=(−a)/c​σ_X​`