`C_(2)H_(5)Br` can be converted into `C_(2)H_(5)-O-C_(2)H_(5)` by:

Options

A. reacting by `C_(2)H_(5)ONa`
B. heating with moist `Ag_(2)O`
C. heating with dry `Ag_(2)O`
D. treating with `C_(2)H_(5)MgBr`

Answer

To convert \( C_2H_5Br \) (ethyl bromide) into \( C_2H_5-O-C_2H_5 \) (diethyl ether), we can follow these steps:

### Step 1: Identify the Reaction Type
We are dealing with the conversion of an alkyl halide (ethyl bromide) into an ether. This typically involves a nucleophilic substitution reaction where the halide is replaced by an alkoxide ion.

### Step 2: Choose the Nucleophile
In this case, the nucleophile will be the ethoxide ion (\( C_2H_5O^- \)). This can be generated from sodium ethoxide (\( C_2H_5ONa \)).

### Step 3: Reaction Mechanism
The reaction can be summarized as follows:
1. Ethyl bromide (\( C_2H_5Br \)) reacts with sodium ethoxide (\( C_2H_5ONa \)).
2. The bromine atom is a good leaving group and will leave, forming a carbocation.
3. The ethoxide ion will attack the carbocation, resulting in the formation of diethyl ether.

### Step 4: Write the Balanced Equation
The balanced chemical equation for the reaction is:
\[ C_2H_5Br + C_2H_5ONa \rightarrow C_2H_5-O-C_2H_5 + NaBr \]

### Step 5: Conclusion
Thus, \( C_2H_5Br \) can be converted into \( C_2H_5-O-C_2H_5 \) using sodium ethoxide (\( C_2H_5ONa \)).

### Summary of Possible Reagents
1. **Option A**: Sodium ethoxide (\( C_2H_5ONa \)) - This is a suitable reagent for the conversion.
2. **Option C**: Dry silver oxide (\( Ag_2O \)) - This can also facilitate the formation of ether from alkyl halides.

### Final Answer
The conversion of \( C_2H_5Br \) to \( C_2H_5-O-C_2H_5 \) can be achieved using:
- **Sodium ethoxide (\( C_2H_5ONa \))** or
- **Dry silver oxide (\( Ag_2O \))**.

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