`3(x+4)-2(x-2)=5(x+5)+3`

5(x-4)-2(3-2x)=4(x+2)-3(2-3x)

((x-1)/(x-2))-((x-2)/(x-3))=((x-3)/(x-4))-((x-4)/(x-5))

Observe the following pattern (1x2)+(2x3)=(2x3x4)/(3)(1x2)+(2x3)+(3x4)=(3x4x5)/(3)(1x2)+(2x3)+(3x4)+(4x5)=(4x5x6)/(3) and find the of (1x2)+(2x3)+(3x4)+(4x5)+(5x6)

Given that (5x - 3)^3 + (2x + 5)^3 + 27(4- 3x)^3 = 9(3 - 5x)(2x + 5)(3x - 4) , then the value of (2x + 1) is:

Solve 5 (x + 2) - 2 (3 - 4x) = 3 (x + 5) - 4 (4 -x)

" Solve : (3x)/(4)-(2x+5)/(3)=(5)/(2)

The equation 5x^(5)+3x^(4)-2x^(3)-2x^(2)+3x+5=0 is a reciprocal equation of

find the range of y=(3)/(x-2)+(4)/(x-3)+(5)/(x-4),x in[(7)/(2),5]

Check whether the following are quadratic equations : (1) (x-3)^(2)=x(2x-5) (2) (2x-3)(8x+1) = (4x+5)(4x-5) (3) (5x+3)(x-2)=(4x+3)(2x-1) (4) (2x+5)^(3)=8(x-1)^(3) (5) x^(2)+7x-8=x(x+5) (6) x^(3)+9x^(2)-7x+2=(x+3)^(3)