In a triangle ABC, if the median AD makes an angle `theta` with `AC and AB = 2AD` then `sintheta =`

In DeltaABC , if the median AD makes an angle theta with AC , and AB=2AD , then sintheta equals

If the median AD of DeltaABC , makes an angle theta with AB then sin(A-theta)=

If the bisector of angle A of the triangle ABC makes an angle theta with BC , then sintheta=

If the bisector of angle A of the triangle ABC makes an angle theta with BC , then sintheta=

If the median AD of a triangle ABC makes an angle theta with side, AB, then sin(A-theta) is equal to

If the median AD of a triangle ABC makes an angle theta with side, AB, then sin(A-theta) is equal to

If the median AD of a triangle ABC makes an angle theta with side, AB, then sin(A-theta) is equal to

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

In a Delta ABC , if the medians AD and BE are such that AD = 4 , angle DAB = pi/6 " and " angle ABE = pi/3 then the area of Delta ABC (in square units) is