" (i) "(x-3)/(5)+(x-4)/(7)=6-(2x-1)/(35)

Find the value of x , (x - 3)/5 + (x - 4)/7 = 6 - (2x - 1)/(35)

(4x+1)/(3)+(2x-1)/(2)=6+(3x-7)/(5)

Solve: (3x)/(7)-(4)/(35)=(2x)/(5)

(6x-7)/(2)+(9-2x)/(5)=12+(x)/(4)-(2)/(3)+(4x)/(3)

(x-1)/(x-2)-(x-2)/(x-3)=(x-5)/(x-6)-(x-6)/(x-7)

((2)/(3)x+4)((3)/(2)x+6)-((1)/(7)x-1)((1)/(7)x+1)

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

7x+(3)/(x)=35(3)/(5)

Assertion (A) : (1)/(5)+(1)/(3.5^(3))+(1)/(5.5^(5))+(1)/(7.5^(7))+…(1)/(2)log((3)/(2)) Reason (R ) : If |x| lt 1 then log_(e )((1+x)/(1-x))=2(x+(x^(3))/(3)+(x^(5))/(5)+…)

(2x-1)/(3)+(3x+2)/(2)+7=(1)/(6)+(4x+3)/(6)