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Find the area of the region lying in th...

Find the area of the region lying in the first quadrant and bounded by `y=4x^2`,`x = 0, y = 1 a n d y = 4`.

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The correct Answer is:
`=1/3 [4^(3//2)-1]=1/3[8-1]=7/3=2 1/3` sq.units
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