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Let T be the triangle with vertices (0,0...

Let T be the triangle with vertices `(0,0), (0,c^2 )and (c, c^2)` and let R be the region between `y=cx and y = x^2` where `c > 0` then

A

Area (R) `= c^(3)/6`

B

Area of R `=c^(3)/3`

C

`Lim_(c rarr 0^(+)) ("Area(T)")/("Area(R)")=3`

D

`Lim_(c rarr 0^(+)) ("Area(T)")/("Area(R)")=3/2`

Text Solution

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The correct Answer is:
A, C
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