Find the point of intersection of the curves `a r g(z-3i)=(3pi)/4a n d arg(2z+1-2i)=pi//4.`

Find the point of intersection of the curves arg(z-3i)=(3 pi)/(4) and arg (2z+1-2i)=pi/4

Number of points of intersections of the curves Arg((z-1)/(z-3))=(pi)/(4) and Arg(z-2)=(3 pi)/(4) are

Number of points of intersections of the curves Arg((z-1)/(z-3))=(pi)/(4) and Arg(z-2)=(3 pi)/(4) are

Number of points of intersections of the curves Arg((z-1)/(z-3))=(pi)/(4) and Arg(z-2)=(3 pi)/(4) is/are

Let A(z_(1)) be the point of intersection of curves arg(z-2+i)=(3 pi)/(4)) and arg(z+i sqrt(3))=(pi)/(3),B(z_(2)) be the point on the curve ar g(z+i sqrt(3))=(pi)/(3) such that |z_(2)-5|=3 is minimum and C(z_(2)) be the centre of circle |z-5|=3. The area of triangle ABC is equal to

The number of points of intersection of the curves represented by arg(z-2-7i)=cot^(-1)(2) and arg ((z-5i)/(z+2-i))=pm pi/2

The pointo fintersection of the cures represented by the equations art(z-3i)= (3pi)/4 and arg(2z+1-2i)= pi/4 (A) 3+2i (B) - 1/2+5i (C) 3/4+9/4i (D) none of these

Find the center of the are represented by arg[(z-3i)/(z-2i+4)]=pi/4

if arg(z+a)=(pi)/(6) and arg(z-a)=(2 pi)/(3) then

Trace the locus of z if arg(z+i)=(-pi)/(4)