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If the cube roots of unity are 1,omega,o...

If the cube roots of unity are `1,omega,omega^2`, then the roots of the equation `(x-1)^3+8=0`, arte

A

`-1,-1,+2omega,-1-2omega^2`

B

`-1,-1,-1`

C

`-1,1-2omega,1-2omega^2`

D

`-1,1+2omega,1+2omega^2`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • If the cube roots of unity are 1, omega and omega^2 , then the roots of the equation (x+1)^3+8=0 , are

    A
    `-1, 1+2 omega, 1+2omega^2`
    B
    `-1, 1-2 omega, 1-2omega^2`
    C
    `-1, -1, -1`
    D
    `-1, -1+2 omega, -1-2omega^2`

  • If the cube roots of unity are 1, omega , omega ^(2) , then the roots of equation ( x - 1)^(3) + 8 = 0 are

    A
    `-1, 1, + 2 omega , 1 + 2 omega^(2)`
    B
    ` - 1 , 1 - 2 omega , 1 - 2 omega^(2)`
    C
    ` - 1, - 1, - 1 `
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  • If 1,omega,omega^(2) are the cube roots of unity, then the roots of the equation (x-1)^(3)+8=0 are

    A
    `-1,1+2omega,1+2omega^(2)`
    B
    `-1,1-2omega,1-2omega^(2)`
    C
    `-1-1-1`
    D
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