If the line `x-y-1 = 0` intersect the parabola `y^2 = 8x` at P and Q, then find the point on intersection of tangents `P and Q`.

Explanation

Let (h, k) be point of intersection of tangents then chord of contact is
`yk=4(x+h)`
`!4x-yk+4h=0` …(i)
But given line is
`!x-y-1=0` ..(ii)
Comparing (i) and (ii),
`therefore4/1=(-k)/(-1)=(4h)/(-1)`
`!h=-1,k=4`
`therefore` point `equiv` (-1, 4)