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Directrix of a parabola is x + y = 2. If...

Directrix of a parabola is x + y = 2. If it’s focus is origin, then latus rectum of the parabola is equal to

A

`sqrt2` units

B

2 units

C

`2sqrt2` units

D

4 units

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The correct Answer is:
To solve the problem, we need to find the length of the latus rectum of a parabola given its directrix and focus. The directrix is given as \( x + y = 2 \) and the focus is at the origin \( (0, 0) \). ### Step-by-Step Solution: 1. **Identify the Directrix and Focus**: - The directrix is given by the equation \( x + y = 2 \). - The focus is at the point \( (0, 0) \). 2. **Convert the Directrix Equation**: - We can rewrite the directrix equation in the form \( Ax + By + C = 0 \): \[ x + y - 2 = 0 \] - Here, \( A = 1, B = 1, C = -2 \). 3. **Calculate the Perpendicular Distance from the Focus to the Directrix**: - The formula for the perpendicular distance \( d \) from a point \( (x_0, y_0) \) to the line \( Ax + By + C = 0 \) is: \[ d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} \] - Substituting \( (x_0, y_0) = (0, 0) \): \[ d = \frac{|1 \cdot 0 + 1 \cdot 0 - 2|}{\sqrt{1^2 + 1^2}} = \frac{|-2|}{\sqrt{2}} = \frac{2}{\sqrt{2}} = \sqrt{2} \] 4. **Relate the Perpendicular Distance to the Latus Rectum**: - The distance \( d \) from the focus to the directrix is equal to \( 2a \), where \( a \) is the distance from the vertex to the focus. - Therefore, we have: \[ 2a = \sqrt{2} \implies a = \frac{\sqrt{2}}{2} \] 5. **Calculate the Length of the Latus Rectum**: - The length of the latus rectum \( L \) of a parabola is given by the formula: \[ L = 4a \] - Substituting the value of \( a \): \[ L = 4 \cdot \frac{\sqrt{2}}{2} = 2\sqrt{2} \] ### Final Answer: The length of the latus rectum of the parabola is \( 2\sqrt{2} \) units. ---
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MOTION-PARABOLA-EXERCISE - I
  1. Latus rectum of the parabola whose focus is (3, 4) and whose tangent a...

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  2. Directrix of a parabola is x + y = 2. If it’s focus is origin, then la...

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  3. Which one of the following equations represents parametrically, parabo...

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  4. The point of intersection of the curve whose parametrix equations are ...

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  5. If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then ...

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  6. let P be the point (1, 0) and Q be a point on the locus y^2= 8x. The l...

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  7. Let N be the foot of perpendicular to the x-axis from point P on the p...

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  8. The locus of the midpoint of the segment joining the focus to a moving...

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  9. If (t^2, 2t) is one end ofa focal chord of the parabola, y^2=4x then ...

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  10. Find the locus of the point of intersection of the perpendicular ta...

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  11. Find the common tangent of x^(2) + y^(2) = 2a^(2) and y^(2) = 8ax.

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  12. The tangents to the parabola x = y^2 + c from origin are perpendicular...

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  13. T P and T Q are tangents to the parabola y^2=4a x at Pa n dQ , respect...

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  14. P Q is a normal chord of the parabola y^2=4a x at P ,A being the verte...

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  15. The normal at the point (bt1^2, 2bt1) on the parabola y^2 = 4bx meets ...

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  16. Locus of the intersection of the tangents at the ends of the normal ch...

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  17. If the normal chhord of the parabola y^(2)=4x makes an angle 45^(@) wi...

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  18. If x+y=k is normal to y^2=12 x , then k is 3 (b) 9 (c) -9 (d) -3

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  19. Tangents are drawn from the points on the line x-y+3=0 parabola y^2=8x...

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  20. The line 4x-7y + 10 = 0 intersects the parabola, y^2 = 4x at the point...

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