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Find the point on the curve y=x^3+x^2+x ...

Find the point on the curve `y=x^3+x^2+x` at which the tangent to the curve is perpendicular to the `x+y=1`

A

(0,0)

B

`(-2/3,-14//27)`

C

`(0,14//27)`

D

`(-2//3,0)`

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The correct Answer is:
A, B
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MOTION-TANGENT & NORMAL-EXERCISE 3
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