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Solve sinx+cosx=1+sinx.cosx...

Solve `sinx+cosx=1+sinx.cosx`

Answer

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Knowledge Check

  • If |[cosx, sinx, cosx], [-sinx, cosx, sinx], [-cosx, -sinx, cosx]|=0 , then x=

    A
    `(2n+1)(pi)/(2), ninZ`
    B
    `(2n+1)(3pi)/(2), ninZ`
    C
    `(2n+1)(pi)/(4), ninZ`
    D
    `(2n+1)pi, ninZ`
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