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The equation 2sin(x/2).cos^2x+sin^2x=2si...

The equation `2sin(x/2).cos^2x+sin^2x=2sin(x/2)sin^2x+cos^2x` has a root for which

A

`sin2x=1`

B

`sin2x=-1`

C

`cosx=1/2`

D

`cos2x=-1/2`

Text Solution

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The correct Answer is:
A, B, C, D
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