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The centre of masses of three particles ...

The centre of masses of three particles of mass `m_(1) = m_(2)=m_3 = 1` kg at the corners of an equilateral triangle of side 1 m will be -

A

0.50m, 0.29m

B

0.43m, 0.50m

C

0.25m, 0.25m

D

0.22m, 0.22m

Text Solution

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The correct Answer is:
A
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