The rms speed of oxygen molecule in a gas at `27^(@)C` would be given by

Explanation

Temperature, `T= 27^(@)C implies 273 + 27 =300K,`
`therefore` Molecular weight of oxygen `=32 xx 10^(-3) kg.`
`R = 8.31 J mol ^(-1) K ^(-1)`
Now, r.m.s velocity is `V = sqrt((3RT)/(M))`
`= sqrt((3xx 8.31xx300)/(32xx10^(-3)))=483.5ms ^(-1)`