Find out the distance travelled by the block on incline before it stops. Initial velocity of the block is 10 m/s and coefficient of friction between the block and incline is `mu = 0.5`.

Explanation

`N=mgcos37^(@)`
`therefore mgsin37^(@)+muN+ma`
`a=10m//s^(2)` down the incline
Now `v^(2)=u^(2)+2as`
`0=10^(2)+2(-10)S`
`therefore S=5m`