Two immiscible of densities `2.5g//cm^(3)` and `0.8g//cm^(3)` are taken in the ratio of their masses as `2:3` respectively find the average density of the liquid conbination.

Explanation

Let masses be 2M and 3M then
`V=V_(1)+V_(2)=((2M)/2.5+(3M)/0.8)cm^(3)`
Total mass `=2M+3M=5M`
Therefore, the average density
`rho_(av)=(5M)/v=(5M)/((2M)/2.5+(3M)/0.8)=5/(2/2.5+3/0.8)`
`=10/9.1g//cm^(3)=1.09g//cm^(3)`