A drop of water of radius 0.0015 mm is falling in air. If the coefficient of viscosity of air is `1.8xx10^(-8)kgm^(-1)s^(-1)` what will be the terminal velocity of the drop. Density of air can be neglected.

Explanation

`V_(T)=2/9 (r^(2)(rho-sigma)g)/(eta)=(2xx[(15xx10^(-4))/100]^(2)xx10^(3)xx9.8)/(9xx1.8xx10^(-5))`
`=2.72xx10^(-4)m//s`