An ice block floats in a liquid whose density is less than water. A part of block is outside the liqud. When whole of ice has melted, the liquid level will

Options

A. rise
B. go down
C. remain same
D. first rise then go down

Answer

To solve the problem, we need to analyze the situation of the ice block floating in a liquid with a density less than that of water. Here’s a step-by-step solution:

### Step 1: Understand the Initial Condition
The ice block is floating in a liquid with a density less than that of water. This means that the ice block is less dense than both the liquid and water. A part of the ice block is above the liquid surface.

### Step 2: Determine the Volume of Ice Displaced
When the ice block is floating, it displaces a volume of liquid equal to the weight of the ice block. The weight of the ice block can be expressed as:
\[ \text{Weight of ice} = \text{Volume of ice} \times \text{Density of ice} \times g \]
where \( g \) is the acceleration due to gravity.

### Step 3: Melting of Ice
When the ice melts, it turns into water. The volume of water produced from the melting ice will be equal to the volume of the ice block because the density of ice is less than that of water.

### Step 4: Effect on Liquid Level
Since the liquid has a density less than that of water, the volume of liquid displaced by the ice block when it was floating will be equal to the weight of the ice block. When the ice melts, the volume of water produced will occupy the same volume as the volume of ice that was submerged in the liquid.

### Step 5: Conclusion
When the ice melts, the volume of water produced will not change the level of the liquid because the volume of water from the melted ice is equal to the volume of liquid that was displaced by the ice block. Therefore, the liquid level will remain the same.

### Final Answer
The liquid level will remain the same.

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