An electron and a photon have got the same de- Broglie wavelength. Prove that total energy of electron is greater than energy of photon.

Explanation

Total energy of electron `E_(e) = mc^2` and
`lamda = (h)/(mv) rArr m = (h)/(lamda v)`
`therefore E_e = (hc^2)/(lamda v)`
For energy of photon `E_P = (hc)/(lamda)` therefore
`(E_e)/(E_P) = (hc^2)/(lamda v) xx (lamda)/(hc) = c/v because c gt v " So " E_e gt E_P `