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(b^(2)-c^(2))cot A+(c^(2)-a^(2))cot B+(a...

(b^(2)-c^(2))cot A+(c^(2)-a^(2))cot B+(a^(2)-b^(2))cot c=0

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In any /_ABC, prove that (b^(2)-c^(2))cot A+(c^(2)-a^(2))cot B+(c^(a)-b^(2))cot C=0

For any triangle ABC, prove that (b^(2)c^(2))cot A+(c^(2)a^(2))cot B+(a^(2)b^(2))cot C=

a^(2)cot A+b^(2)cot B+c^(2)cot C=

a^(2) cot A+ b^(2) cot B+ c ^(2) cot C =

In a triangle ABC,prove that (cot((A)/(2))+cot((B)/(2))+cot((C)/(2)))/(cot A+cot B+cot(C))=((a+b+c)^(2))/(a^(2)+b^(2)+c^(2))

In any triangle ABC, prove that, (b-c)cot 'A/2' + (c-a) cot 'B/2' + (a-b) cot 'C/2'=0

cot((A)/(2))+cot((B)/(2))+cot((C)/(2))=

cot((A)/(2))+cot((B)/(2))+cot((C)/(2))=cot((A)/(2))cot((B)/(2))cot((C)/(2))

In a triangle ABC if cot((A)/(2))*cot((B)/(2))=c,cot((B)/(2))*cot((C)/(2))=a and cot((C)/(2))*cot((A)/(2))=b then (1)/(s-a)+(1)/(s-b)+(1)/(s-c)=

if A+B+C=pi prove that cot((A)/(2))+cot((B)/(2))+cot((C)/(2))=cot((A)/(2))xx cot((B)/(2))xx cot((C)/(2))