If `p_1 and p_2`, be the lengths of the perpendiculars from theorigin upon the lines `4x+3y = 5cosalpha and 6x – 8y = 5 sinalpha` respectively, show that, `p_1^2 + 4p_2^2 = 1`.

If p_(1)andp_(2) be the lenghts of the perpendiculars from the origin upon the lines 4x+3y=5cosalphaand 6x-8y=5sinalpha repectively , show that p_(1)^(2)+4p_(2)^(2)=1 .

If p_1a n d\ p_2 are the lengths of te perpendiculars from the origin upon the lines x\ s e ctheta+h y cos e ctheta=a\ a n d\ xcostheta-ysintheta=acos2theta respectively, then 4p1 2+p2 2=a^2 b. p1 2-4p2 2=a^2 c. p1 2+p2 2=a^2 d. none of these

If p_1a n d\ p_2 are the lengths of te perpendiculars from the origin upon the lines x\ s e ctheta+h y cos e ctheta=a\ a n d\ xcostheta-ysintheta=acos2theta respectively, then a.4p1 2+p2 2=a^2 b. p1 2-4p2 2=a^2 c. p1 2+p2 2=a^2 d. none of these

If 2p is the length of perpendicular from the origin to the lines x/a+ y/b = 1, then a^2,8p^2,b^2 are in

If p_1 and p_2 be the lengths of perpendiculars from the origin on the tangent and normal to the curve x^(2/3)+y^(2/3)= a^(2/3) respectively, then 4p_1^2 +p_2^2 =

Distance of the straight line 4x+3y=5 cosalpha and 6x-8y= 5 sinalpha from the origin are p_1 and p_2 respectivley show that p_1^2+4p_2^2=1

If p_(1) and p_(2) be the lengths of the perpendiculars from the origin upon the tangent and normal respectively to the curve x^((2)/(3)) +y^((2)/(3)) = a^((2)/(3)) at the point (x_(1), y_(1)) , then-