(v)(3y-2)+i(7-2x)=0

Find x and y if: (3y-2)+i(7-2x)=0

Find x and y, if (3y - 2) +i(7-2x) = 0.

Find x and y if: (3y-2)+i(7-2x)=0

Find the values of x and y from the following : (i) (3x -7)+2iy=-5y+(5+ x)i (ii) 2x i+12= 3y-6i (iii) z=x+iy and i(z+2)+1=0 (iv) ((1+i)x-2i)/(3+i)+((2-3i)y+i)/(3-i)=i (v) (3x-2iy)(2+i)^(2)=10(1+i)

Find the values of x and y from the following : (i) (3x -7)+2iy=-5y+(5+ x)i (ii) 2x i+12= 3y-6i (iii) z=x+iy and i(z+2)+1=0 (iv) ((1+i)x-2i)/(3+i)+((2-3i)y+i)/(3-i)=i (v) (3x-2iy)(2+i)^(2)=10(1+i)

A point which lies between 2x+3y-7=0 and 2x+3y+12-0 is (i)(5,1)( (ii) (-1,3)( iii) (-3,-5)( iv )(7,-1)

Equation of the circle cutting orthogonal these circles x^(2)+y^(2)-2x-3y-7=0x^(2)+y^(2)+5x-5y+9=0 and x^(2)+y^(2)+7x-9y+29=0 is:

Find the zeros of these polynomials and verify the relationship between zeros and coefficients. i] f(x) = x^(2) - (sqrt(3) + 1) x + sqrt(3) ii] f(v) = v^(2) + 4 sqrt(3) v - 15 iii] q(y) = 7y^(2) (11)/(3) y - (2)/(3)