Three dice are thrown together. Find the probability of getting a total of at least 6.

Explanation

`6*6*6=216`

`P_1=1-P`

`{(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,2,2),(2,2,1),(2,1,2),(1,1,3),(3,1,1),(1,3,1)}`

P(sum<6)=10/216

P(sum>6)=1-P(sum <6)

`=1-10/216=206/216=103/108`.