n identical drops each of radius r combine into a big drop of radius R.The energy loss during this formation is 3E where E is the energy of the bigger drop.The value of 'n' is :

n droplets of equal size and each of radius r coalesce to form a bigger drop of radius R. the energy liberated is equal to

n' droplets of equal of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to ( T = Surface tension of water )

A large number of liquid drops each of radius 'a' coalesce to form a single spherical drop of radish b. The energy released in the process is converted into kinetic energy of the big drops formed. The speed of big drop will be

A large number of droplets, each of radius a, coalesce to form a bigger drop of radius b . Assume that the energy released in the process is converted into the kinetic energy of the drop. The velocity of the drop is sigma = surface tension, rho = density)

When a big drop of water is formed from n small drops of water, the energy oss is 3E, where, E is the energy of the bigger drop. If R is the radius of the bigger drop and r is the radius of the smaller drop then number of smaller drops (n) is?

A number of droplets, each of radius r , combine to form a drop of radius R . If T is the surface tension, the rise in temperature will be

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

If a number of litle of droplets of water of surface tension S, all of the same radius r combine to from a single drop of radius R and the energy relased is converted into kinetic energy. Find the velocity acquired by the bigger drop. If the energy relased in converted inot heat, find the rise in temperature.

Some drops each of radius r coalesce to form a large drop of radius R . The surface tension T. Find the change in surface energy per unit volume?

Two mercury drops each of radius r merge to form a bigger drop. Calculate the surface energy released.