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A die is loaded in such a way that a way that each odd number is twice as likely to occur as each even number. Find P(G), where G is the event that a number greater than 3 occurs on a single roll of the die.

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P(E)=x
P(0)=2P(E)=2x
3(2x)+3(X)=1
9x=1
x=1/9
`P(G)=1/9+2/9+1/9=4/9`.
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