A bag contains 50 tickets numbered 1, 2, 3, .., 50 of which five are drawn at random and arranged in ascending order of magnitude `(x_1ltx_2ltx_3ltx_4ltx_5)` find the probability that`x_3=30.`

Explanation

To solve the problem, we need to find the probability that \( x_3 = 30 \) when we draw 5 tickets from a bag containing tickets numbered from 1 to 50, arranged in ascending order.

### Step-by-Step Solution:

1. **Understanding the Condition**:
We want \( x_3 = 30 \). This means that when we arrange our 5 drawn tickets in ascending order, the third ticket must be 30. Therefore, we need to have 2 tickets that are less than 30 and 2 tickets that are greater than 30.

2. **Choosing Tickets Less Than 30**:
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