If the letters of the word ALGORITHM are arranged at random in row what is the probability that the letters GOR must remain together as a unit?

Explanation

As all are unique alphabets so use permutations to get your answer i.e. Total words can be formed will be 9!


When GOR is together i.e `7!3! `


So probability will be `(7!3!)/(9!)= (3×2)/(9×8)=1/12`