`7x^2-19x-6=?`

Resolve quadratic trinomial into factors: 7x^2-19 x-6

If alpha ,beta are the roots of the equation 9x^(2)-7x+6=0 then the equation whose roots are 3 alpha+2 , 3 beta+2 is - 1) 3x^(2)+19x-144=0 2) 3x^(2)-19x+144=0 3) 3x^(2)-19x+44=0 4) 3x^(2)-19x-44=0

Factorize :2x^(4)+x^(3)-14x^(2)-19x-6

Obtain all zeros of the polynomial f(x)=2x^(4)+x^(3)-14x^(2)-19x-6, if two of its zeros are -2 and 1

Factorise : x^(2)-19x-20

x^(2)-19x+84

Factorise: 7x ^(2) - 19 x -6

Using the Remainder Theorem, factorise each of the following completely: (i) 3x^3+2x^(2)-19x+6 (ii) 2x^(3)+x^2-13x+6 (iii) 3x^(3)+2x^2-23x-30 (iv) 4x^3+7x^2-36x-63 (v) x^3+x^2-4x-4

…………is one of the factors of 2x^(4) + x^(3) - 14 x^(2) - 19x - 6 .