Four persons are to be chosen at random from a group of 3 men, 2 women and 4 children. Find the probability of selecting: (i)1man  1woman and 2 children (ii)Exactly 2 children             (iii) 2 women

Explanation

Total persons=2+3+4=9

total ways=`.^9C_4`

1)`.^3C_!*.^2C_1*.^4C_2` favorable cases

`P=(.^3C_1*.^2C_1.^4C_1)/(.^9C_4)`

`P=2/7`

2)Exactly 2 children

Case 1) 2 childdren 1 men 1 women

`.^4C_2*.^3C_1*.^2C_1`

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