If `theta=pi/(2^n+1)` , prove that: `2^ncosthetacos2thetacos2^2 cos2^(n-1)theta=1.`

If theta=pi/(2^n+1) , prove that: 2^ncosthetacos2thetacos2^2thetacos2^(n-1)theta=1.

If theta=pi/(2^n+1) , prove that: 2^ncosthetacos2thetacos2^2theta....... cos2^(n-1)theta=1.

If theta=(pi)/(2^(n)+1), prove that: 2^(n)cos theta cos2 theta cos2^(2)...*cos2^(n-1)theta=1

If theta = (pi)/(2 ^(n) +1) prove that 2 ^(n) cos theta cos 2 theta cos 2 ^(2) theta…. Cos 2 ^(n -1) theta =1

If theta = (pi)/(2 ^(n) +1) prove that 2 ^(n) cos theta cos 2 theta cos 2 ^(2) theta…. Cos 2 ^(n -1) theta =1

If theta=pi/(2^n+1) then costhetacos2thetacos2^2theta....cos2^(n-1)theta is equal to

If theta = pi/(2^(n) + 1), "show that",2^(n) cos theta cos 2 theta cos2^(2) theta cos2^(3) theta.... cos2^(n-1) theta = 1.

If theta=pi/(2^n+1) then cos theta cos 2 theta cos 2^(2) theta...... Cos2^(n-1) theta is equal to

If theta=(pi)/(7), prove that cos theta cos2 theta cos3 theta=(1)/(2^(3))