[20+3y+5=0],[3x-8y-12=0]

find x and y : 2x+3y-8=0, 3x+y-5=0

The linear system of equations 8x-3y-5z=0,5x-8y+3z=0 and 3x+5y-8z=0

Coordinates of the orthocentre of the triangle whose sides are 3x -2y = 6, 3x + 4y + 12 = 0 and 3x-8y+12=0 is

Coordinates of the orthocentre of the triangle whose sides are 3x-2y=6,3x+4y+12=0 and 3x-8y+12=0is

Solve using the method of substitution. ( i) 2x-3y =7,5x +y=9 (ii) 1.5x+ 0.1 y =6.2,3x -0.4y=11.2 (iii) 10% of x +20% of y =24, 3x-y=20 (iv) sqrt2x -sqrt 3y =1, sqrt 3x -sqrt 8y =0

Show that the lines 3x-4y+5=0,7x-8y+5=0 and 4x+5y=45 are concurrent.

Four lines x+3y-10=0,x+3y-20=0,3x-y+5=0 and 3x-y-5=0 form a figure which is.

Four lines x+3y-10=0,x+3y-20=0,3x-y+5=0 and 3x-y-5=0 form a figure which is.

Orthocentre of the triangle formed by lines 2x+3y-5=0 ,5x+8y+3=0,6x-4y-2=0 is :

{:(2x + 3y + 5 = 0),(3x - 2y - 12 = 0):}