" Q."3" if "(2)=4,f'(2)-1," then "It_(x rarr2)((2f(x)-4f^(2)))/(2-x))=

lim_(x rarr2)(f(x)-f(2))/(x-2)=

if f(2)=4,f'(2)=1 then lim_(x rarr2)(xf(2)-2f(x))/(x-2)

if f(2)=4,f'(2)=1 then lim_(x rarr2)(xf(2)-2f(x))/(x-2)

Let f(2)=4,f'(2)=4 .Then Lt_(x rarr2)(xf(2)-2f(x))/(x-2) is :

If f(2)=4 and f'(2)=1, then find (lim)_(x rarr2)(xf(2)-2f(x))/(x-2)

If f(2)=2 and f'(2)=1, then find lim_(x rarr2)(xf(2)-2f(x))/(x-2)

If f(2)=2,f'(2)=1. then lim_(x rarr2)(2x^(2)-4f(x))/(x-2)=(i)-4(ii)-2(iii)2(iv)

Let f be real-valued function such that f(2)=2 and f'(2)=1 then lim_(x rarr2)int_(2)^(f(x))(4t^(3))/(x-2)backslash dt is equal to :

If f(2) = 4 and f^(')(2) =1 then lim_(x rarr 2) (x f(2)-2f (x))/(x-2)

Q.if f(3)=6 and f'(3)=2, then lim it_(x rarr3)(xf(3)-3f(x))/(x-3) is given by :(A)6 (b) 4(C)0(D)1