cos(2cos^(-1)x+sin^(-1)x)

Evaluate: cos (2 cos ^(-1) x +sin ^(-1) x ) at x = (1)/(5).

Find the value of cos( 2 cos^(-1) x + sin^(-1) x) " when " x = 1/5

Find the value of cos( 2 cos^(-1) x + sin^(-1) x) " when " x = 1/5

Evaluate: cos (2 cos ^(-1) x +sin ^(-1) x ) at x = (1)/(5).

Find the value of cos( 2 cos^(-1) x + sin^(-1) x) " when " x = 1/5

The value of cos(2cos^-1x+sin^-1x) at x= 1/5 is (A) 1 (B) 3 (C) 0 (D) (-2sqrt(6))/5

f(x)=sin{cot^-1(x+1)}-cos(tan^-1x) a=costan^-1sincot^-1x b=cos(2cos^-1x+sin^-1x) Answer the following question on above passage: The value of x for which f(x)=0 is

Evaluate "cos"(2"cos"^(-1)x+"sin"^(-1)x) at x=1/(5) , where 0le"cos"^(-1)xlepiand-pi/(2)le"sin"^(-1)xlepi/(2) .

What is the value of (d)/(dx)[sin^(-1){cos(sin^(-1)x)}+cos^(-1) {sin(cos^(-1)x)}]?