" If "y=tan^(-1)[(2^(x))/(ln2x+1)]" then dy "a+x=0

if y = tan^-1(2^x/(1+2^(2x+1))) then dy/dx at x =0 is

if y = tan^-1(2^x/(1+2^(2x+1))) then dy/dx at x =0 is

If tan y=(2^(x))/(1+2^(2x+1)), then (dy)/(dx) at x=0 is -(3)/(10) (b) -(3)/(10)ln2-(1)/(10)(d)-(1)/(10)ln2

Let y_1=tan^(-1)((sqrt(1+x^2)-1)/x) and y_2=tan^(-1)((2xsqrt(1-x^2))/(1-2x^2)) then (dy_1)/(dy_2)=

If log (x^(2)+y^(2))=tan^(-1)((y)/(x)), then show that (dy)/(dx)=(x+y)/(x-y)

If y=log((1-x^(2))/(1+x^(2)))," then "(dy)/(dx)=