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On simplification factor of ""((5^(n+2)-6*5^(n+1))/(13*5^n-2*5^(n+1))) is

(5^(n+2)-6xx5^(n+1))/(13xx5^(n)-2xx5^(n+1))

lim_(n rarr oo)(5^(n+1)+3^(n)-2^(2n))/(5^(n)+2^(n)+3^(2n+3))

Simplify : frac(5^n xx 25^(2n-2))(5^(3n-2) xx 10^-1)

The sum of first n terms of an AP is (5n - n^(2)). The nth term of the AP is

The sum of first n terms of an A.P.is 5n-n^(2) . Find the nth term of this A.P.

The value of lim_(x rarr oo)(5^(n+1)+3^(n)-2^(2n))/(5^(n)+2^(n)+3^(2n+1))

5 n+2 −6 xx 5 n+1/13 xx 5 n − 2 *5 n+1 is equal to

sum_ (n = 1) ^ (oo) (5 ^ (n) -2 ^ (n)) / (10 ^ (n))