" 9) "2m(m-24)=50

Solve the following quadratic equation by factorization: 2m(m-24)=50

Solve the following quadratic equations by factorization. 2m (m - 24) = 50

Solve the following quadratic equations by factorization. 2m(m-24)=50

If f(m) = sum_(i=0)^m ((30),(30-i)) ((20),(m-i)) where ((p),(q)) = pCq, then (A) maximum value of f(m) is 50C 25 (B) f(0)+f(1) +...+f(50) =2^50 (C) f(m) is always divisible by 50 (1<=m<=49) (D)sum_(m=0)^(50) (f(m))^2=100C50

If the straight line y=mx+c passes through the points (2,4) and (-3,6) , then the value of m and c are (i) m=-(2)/(5),c=(24)/(5) (ii) m=(2)/(5),c=(24)/(5) (iii) m=-(2)/(5),c=-(24)/(5) (iv) m=(2)/(5),c=-(24)/(5)

If the straight line y=mx+c passes through the points (2,4) and (-3,6) , then the value of m and c are (i) m=-(2)/(5),c=(24)/(5) (ii) m=(2)/(5),c=(24)/(5) (iii) m=-(2)/(5),c=-(24)/(5) (iv) m=(2)/(5),c=-(24)/(5)

If the straight line y=mx+c passes through the points (2,4) and (-3,6) , then the value of m and c are (i) m=-(2)/(5),c=(24)/(5) (ii) m=(2)/(5),c=(24)/(5) (iii) m=-(2)/(5),c=-(24)/(5) (iv) m=(2)/(5),c=-(24)/(5)

A block of mass 'm' is raised by a man of mass m_2 in two different ways as shown ( m_1 = 25kg, m_2 = 50kg)

A block of mass 'm' is raised by a man of mass m_2 in two different ways as shown ( m_1 = 25kg, m_2 = 50kg)