9x^(2)+6x+1=0

factorise 9x^(2)-6x+1

Solve by the method of completing the square: (1) 9x^(2)-15x+6=0 (2) 5x^(2)-6x-2=0

IF sqrt(9x^2 + 6x +1) lt (2-x) then

IF sqrt(9x^2 + 6x +1) lt (2-x) then

Find the values of k for which the given quadratic equation has real and distinct roots: (i) kx^(2)+6x+1=0" "(ii)" "x^(2)-kx+9=0 (iii) 9x^(2)+3kx+4=0" "(iv)" "5x^(2)-kx+1=0