(theta)(99)^(3)

((sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+(cos^(3)theta+sin^(3)theta)/(cos theta+sin theta))=?

((sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+(cos^(3)theta+sin^(3)theta)/(cos theta+sin theta))=?

Evaluate using the suitable identity. (99)^(3)

Evaluate the following uing suitable identities : (99)^(3)

((cos2theta+isin2theta)^(3)(cos3theta-isin3theta)^(4))/((cos3theta+isin3theta)^(2)(cos4theta+isin4theta)^(-3))

If cos h(3 theta) = 99 then cos h theta =

Let 0 lt theta lt 90^(@) and 100 theta = 90^(@) . If alpha = prod_(n=1)^(99) cot n theta , then which one of the following is correct?

Find the value of (99)^(3) using binomial expansion.