|[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]|

Using properties of determinants prove the following. abs[[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]]=(a+b+c)^3

Prove that abs[[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]]=(a+b+c)^3

Prove that the following. [[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]]=(a+b+c)^3

Show that abs[[a-b-c,2a,,2a],[2b,b-c-a,,2b],[2c,2c,,c-a-b]]=(a+b+c)^3

If Delta=[(a-b-c,2a,2a),(2b,b-c-a,2b),(2c,2c,c-a-b)] Perform R_1rarrR_1+R_2+R_3 on Delta

If Delta=[(a-b-c,2a,2a),(2b,b-c-a,2b),(2c,2c,c-a-b)] Perform R_1rarrR_1+R_2+R_3 on Delta . Take (a+b+c) common from R_1 & rewrite Delta .

det[[ prove that ,2aa-b-c,2a,2a2b,b-c-a,2b2c,2c,c-a-b]]=(a+b+c)^(3)

If A= [{:(a-b-c, 2a,2a), (2b, b-c-a, 2b),(2c, 2c, c-a-b):}] = (a +b+c) (x +a +b+c)^(2), x ne 0 " and " a +b +c ne 0 , then x is equal to

prove that [ [a-b-c , 2a , 2a ] , [2b , b-c-a , 2b ] ,[2c ,2c,c-a-b]]= (a+b+c)^3

prove that [ [a-b-c , 2a , 2a ] , [2b , b-c-a , 2b ] ,[2c ,2c,c-a-b]] = (a+b+c)^3