cot(tan^(-1)x+cot^(-1)x)=?

The value of cot(tan^(-1)2x+cot^(-1)2x) is ... (A) 0 (B) 2x (C) 4x (D) pi+2x A B C D

int\ (tan^(-1)x - cot^(-1)x)/(tan^(-1)x + cot^(-1)x) \ dx equals

The value of 2tan^(-1)(cos ec tan^(-1)x-tan cot^(-1)x) is equal to (a)cot ^(-1)x( b ) (cot^(-1)1)/(x) (c)tan ^(-1)x (d) none of these

Evaluate: (i) sin(tan^(-1)x+(tan^(-1)1)/(x)) for x>0( ii) cot(tan^(-1)a+cot^(-1)a)

int_((pi)/(6))^((pi)/(4))(tan x+cot xdx)/(tan^(-1)x+cot^(-1)x)

If y=(tan^(-1)x-cot^(-1)x)/(tan^(-1)x+cot^(-1)x) then (dy)/(dx)=

int(tan^(-1)x-cot^(-1)x)/(tan^(-1)x+cot^(-1)x)dx equals

If y=(tan^(-1)x-cot^(-1)x)/(tan^(-1)x+cot^(-1)x) , find ((dy)/(dx))_(x=-1)

If y=(tan^(-1)x-cot^(-1)x)/(tan^(-1)x+cot^(-1)x) , find ((dy)/(dx)])_(x=-1) 0 (b) 1 (c) 2//pi (d) -1

If y=(tan^(-1)x-cot^(-1)x)/(tan^(-1)x+cot^(-1)x), find (dy)/(dx)]_(x=-1)0(b)1(c)2/ pi(d)-1